Hkcee 2010 Maths Paper 2 Solution [2021] ◆

Semi-perimeter ( s = (13+14+15)/2 = 21 ) Step 2: Area = ( \sqrt21(21-13)(21-14)(21-15) = \sqrt21 \times 8 \times 7 \times 6 ) Step 3: = ( \sqrt7056 = 84 ) Answer: A

Critical points: ( x = 1 ) and ( x = -2 ) (undefined). Step 2: Test intervals: ( x < -2 ) → positive; between -2 and 1 → negative or zero; ( x > 1 ) → positive. Step 3: Include ( x = 1 ), exclude ( x = -2 ). Answer: ( -2 < x \le 1 ) → Option C. hkcee 2010 maths paper 2 solution

(Note: Actual sequence may vary slightly by version – always cross-check with question order.) Semi-perimeter ( s = (13+14+15)/2 = 21 )

You can access the full paper and marking schemes through these hosted documents: Answer: ( -2 &lt; x \le 1 ) → Option C