Practice Problem 7.12 Fundamentals Of Electric Circuits

Vi(s) = R1IL(s) + L1(sIL(s) - iL(0))

i open paren t close paren equals 4 plus open bracket 6 minus 4 close bracket e raised to the negative 10 t power practice problem 7.12 fundamentals of electric circuits

At t=0, switch opens. Now circuit: inductor and ( R_2 ) in parallel, with no source — but careful: after opening, source and ( R_1 ) are disconnected. Inductor discharges through ( R_2 ). Final current = 0 A. Vi(s) = R1IL(s) + L1(sIL(s) - iL(0)) i

Since current through an inductor cannot change instantaneously, the current just after the switch opens is the same as just before: 3. Analyze for When the switch opens for Final current = 0 A

The solution to Practice Problem 7.12 from Fundamentals of Electric Circuits This problem involves finding the inductor current RL circuit where a switch changes position at

Vi(s) = R1IL(s) + L1(sIL(s) - iL(0))

i open paren t close paren equals 4 plus open bracket 6 minus 4 close bracket e raised to the negative 10 t power

At t=0, switch opens. Now circuit: inductor and ( R_2 ) in parallel, with no source — but careful: after opening, source and ( R_1 ) are disconnected. Inductor discharges through ( R_2 ). Final current = 0 A.

Since current through an inductor cannot change instantaneously, the current just after the switch opens is the same as just before: 3. Analyze for When the switch opens for

The solution to Practice Problem 7.12 from Fundamentals of Electric Circuits This problem involves finding the inductor current RL circuit where a switch changes position at