If you cannot find an official answer key, or if you want to avoid the temptation of cheating, try these alternatives:
**Problem:** Count distinct words in a text file. spark 2 workbook answers
| Operation | PySpark | Scala | |-----------|---------|-------| | **Read CSV** | `spark.read.option("header","true").csv(path)` | `spark.read.option("header","true").csv(path)` | | **Write Parquet** | `df.write.parquet("out.parquet")` | `df.write.parquet("out.parquet")` | | **Cache** | `df.cache()` | `df.cache()` | | **Repartition** | `df.repartition(10)` | `df.repartition(10)` | | **Window** | `from pyspark.sql.window import Window` | `import org.apache.spark.sql.expressions.Window` | | **UDF** | `spark.udf.register("toUpper", lambda s: s.upper(), StringType())` | `udf((s: String) => s.toUpperCase, StringType)` | | **Streaming read** | `spark.readStream.format("socket")...` | `spark.readStream.format("socket")...` | | **Stop Spark** | `spark.stop()` | `spark.stop()` | If you cannot find an official answer key,
: Level 2 is where foundational English grammar starts to get complex. Mastering these basics now prevents major "holes" in your knowledge at Level 3 and 4. Study Tip: Use the "Key" as a Tool If you do find the answer key, use it for self-correction Study Tip: Use the "Key" as a Tool
: The official Digibooks App often provides interactive versions where students can receive immediate feedback.
